CUET Preparation Today
The principal value of $\cos^{-1} \left( \cos \frac{13\pi}{6} \right)$ is |
$\frac{13\pi}{6}$ $\frac{\pi}{2}$ $\frac{\pi}{3}$ $\frac{\pi}{6}$ |
$\frac{\pi}{6}$ |
The correct answer is Option (4) → $\frac{\pi}{6}$ ## $\cos^{-1} \left( \cos \frac{13\pi}{6} \right) = \cos^{-1} \left( \cos \left( 2\pi + \frac{\pi}{6} \right) \right)$ $= \cos^{-1} \left( \cos \frac{\pi}{6} \right) = \frac{\pi}{6}$ |
