Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Vectors

Question:

If $\vec a,\vec b,\vec c$ are non-coplanar vectors and λ is a real number, then $\begin{bmatrix}λ(\vec a+\vec b) &λ^4\vec b& λ\vec c\end{bmatrix}=\begin{bmatrix}\vec a&\vec b+\vec c&\vec b\end{bmatrix}$ for

Options:

exactly two values of λ

exactly three values of λ

no value of λ

exactly one value of λ

Correct Answer:

no value of λ

Explanation:

We have,

$\begin{bmatrix}λ(\vec a+\vec b) &λ^4\vec b& λ\vec c\end{bmatrix}=\begin{bmatrix}\vec a&\vec b+\vec c&\vec b\end{bmatrix}$

$⇒λ^4\begin{bmatrix}\vec a+\vec b&\vec b&\vec c\end{bmatrix}=\begin{bmatrix}\vec a&\vec b+\vec c&\vec b\end{bmatrix}$

$⇒λ^4\left\{[\vec a\,\,\vec b\,\,\vec c]+[\vec a\,\,\vec b\,\,\vec c]\right\}=\left\{[\vec a\,\,\vec b\,\,\vec b]+[\vec a\,\,\vec c\,\,\vec b]\right\}$

$⇒λ^4[\vec a\,\,\vec b\,\,\vec c]=-[\vec a\,\,\vec b\,\,\vec c]$

$⇒(λ^4+1)[\vec a\,\,\vec b\,\,\vec c]=0$

This is not true for any real value of λ as $[\vec a\,\,\vec b\,\,\vec c]≠0$.