If $x< y $ and $z< 0$ then :

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Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Algebra

Question:

If $x< y $ and $z< 0$ then :

Options:

$x+ z > y-z $

$\frac{x}{z} < \frac{y}{z}$

$\frac{x}{z} > \frac{y}{z}$

$x+z > y + z $

Correct Answer:

$\frac{x}{z} > \frac{y}{z}$

Explanation:

The correct answer is Option (3) → $\frac{x}{z} > \frac{y}{z}$

$x<y$ [Given]

$⇒\frac{x}{z} > \frac{y}{z}$ [$∵ z<0$ [Given]]