Practicing Success
A person has to cover a distance of 96 km. If he increases his speed by 4 km/hr he reaches 4 hour early. Find his initial speed (in km/hr). |
10 14 8 12 |
8 |
Let the initial speed = x km/hr ATQ, \(\frac{96}{x}-\frac{96}{x+4}=4\) let x = 8 (by using option) \(\frac{96}{8}-\frac{96 }{12}=4\) 12 – 8 = 4 (satisfied) so, x = 8 |