Simplify. $\frac{cos^4 θ−sin^4 θ}{sin^2 θ}$
Answer & explanation
Correct answer: option 3
$\frac{cos^4 θ−sin^4 θ}{sin^2 θ}$
= \(\frac{( cos²θ - sin²θ ) . ( cos²θ + sin²θ ) }{sin²θ}\)
{ using , cos²θ + sin²θ = 1 }
= \(\frac{( cos²θ - sin²θ ) . 1 }{sin²θ}\)
= \(\frac{( cos²θ }{sin²θ}\) - \(\frac{( sin²θ }{sin²θ}\)
= cot²θ - 1