The conductivity of 0.20 M KCl solution at 298 K is 0.025 S cm-1. Calculate its molar conductivity.
Answer & explanation
Correct answer: option 2
Molar conductivity, λm = \(\frac{1000 × K}{M}\)
λm = \(\frac{1000 × 0.025}{0.20}\) = 125 S cm2 mol-1
The conductivity of 0.20 M KCl solution at 298 K is 0.025 S cm-1. Calculate its molar conductivity.
Correct answer: option 2
Molar conductivity, λm = \(\frac{1000 × K}{M}\)
λm = \(\frac{1000 × 0.025}{0.20}\) = 125 S cm2 mol-1