The conductivity of 0.20 M KCl solution at 298 K is 0.025 S cm-1. Calculate its molar conductivity.

225.0 S cm2 mol-1 125.0 S cm2 mol-1 325.0 S cm2 mol-1 425.0 S cm2 mol-1

125.0 S cm2 mol-1

Molar conductivity, λm = \(\frac{1000 × K}{M}\) λm = \(\frac{1000 × 0.025}{0.20}\) = 125 S cm2 mol-1