A coil with an inductance of 0.2 H has an inductive reactance of 62.8 \( \Omega \) at a certain frequency. The frequency is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( 50\,\mathrm{Hz} \)
The inductive reactance of a coil is \( X_{L} = \omega L = 2\pi f L \), so the frequency follows from \( X_{L} \) and \( L \).
\( \displaystyle f = \frac{X_{L}}{2\pi L} = \frac{62.8}{2 \times 3.14 \times 0.2} = \frac{62.8}{1.256} = 50\,\mathrm{Hz} \)