A coil with an inductance of 0.2 H has an inductive reactance of 62.8 Ω at a certain frequency. The frequency is

50 Hz

The correct answer is Option (4) → 50 Hz

Given:

Inductance, $L = 0.2\ \text{H}$

Inductive reactance, $X_L = 62.8\ \Omega$

Inductive reactance formula: $X_L = 2 \pi f L$

Substituting values:

$62.8 = 2 \pi f (0.2)$

$62.8 = 0.4 \pi f$

$f = \frac{62.8}{0.4 \pi} = \frac{62.8}{1.256} \approx 50\ \text{Hz}$

∴ Frequency = 50 Hz