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If, $\frac{r}{13}+\frac{13}{r} = 1$ then the value of r3 is: |
-2157 2197 2157 -2197 |
-2197 |
If, $\frac{r}{13}+\frac{13}{r} = 1$ Then the value of r3 is? If we have x + \(\frac{1}{x}\) = 1 Then x3 = -1 always (\(\frac{r}{13}\))3 = -1 r3 = -2197 |
