A transformer with turns ratio $\frac{N_1}{N_2}=\frac{100}{1}$ is connected to a 240 V ac supply. If the primary and secondary resistance are 1.0 kΩ and 1 Ω respectively, then find the output power?

5.76 W

The correct answer is Option (1) → 5.76 W

for an ideal transformer,

$\frac{V_1}{V_2}=\frac{N_1}{N_2}$

$\frac{N_1}{N_2}$, Turns Ratio = 100 : 1 [Given]

Primary Voltage $(V_1)$ = 240 V

Primary Resistance $(R_1)$ = 1000Ω

Secondary Resistance $(R_2)$ = 1Ω

$\frac{V_1}{V_2}=\frac{N_1}{N_2}$

$⇒V_2=\frac{V_1}{100}=\frac{240}{100}=2.4V$

$∴I_2=\frac{V_2}{R}=\frac{2.4}{1}=2.4A$ [By Ohm's law]

$P_{output}=V_2×I_2=2.4V×2.4A$

$=5.76W$