The HCF of $\frac{1}{2},\frac{3}{4},\frac{5}{6}$ and $\frac{7}{8}$ is :
Answer & explanation
Correct answer: option 2
HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)
The given fractions are : $\frac{1}{2},\frac{3}{4},\frac{5}{6}$ and $\frac{7}{8}$.
LCM of 2, 4, 6, 8 = 24
HCF of 1, 3, 5, 7 = 1
The HCF of $\frac{1}{2},\frac{3}{4},\frac{5}{6}$ and $\frac{7}{8}$ = \(\frac{1}{24}\)