Practicing Success
Practicing Success
CUET Preparation Today
Five equal resistances each of resistance R are connected as shown in the figure. A battery of V volt is connected between A and B. The current flowing in AFCEB will be:
|
$\frac{3 V}{R}$ $\frac{V}{R}$ $\frac{V}{2 R}$ $\frac{2 V}{R}$ |
$\frac{V}{2 R}$ |
The equivalent circuit is as shown in figure (i), which is a balanced wheatstone bridge. There will be no current in arm CD. Hence the effective circuit will be as shown in figure (ii).
The resistance of arm AFCEB = R + R = 2R When a potential difference V is applied across A and B, then current in arm AFCEB is I = $\frac{V}{2R}$ |
