CUET Preparation Today
Match List-I with List-II.
Choose the correct option from the ones given below : | ||||||||||||||||||||
(A)-(II), (B)-(III), (C)-(IV), (D)-(I) (A)-(IV), (B)-(I), (C)-(II), (D)-(III) (A)-(I), (B)-(IV), (C)-(II), (D)-(III) (A)-(IV), (B)-(I), (C)-(III), (D)-(II) |
(A)-(IV), (B)-(I), (C)-(II), (D)-(III) |
The correct answer is Option (2) → (A)-(IV), (B)-(I), (C)-(II), (D)-(III) (A) $\int\limits^{1}_{-1}|x|dx=2\int\limits_0^1x\,dx=1$ (IV) (B) $\int\limits^{\frac{\pi }{2}}_{-\frac{\pi }{2}}\sin x\, dx=0$ (Odd function) (I) (C) $\int\limits^{\frac{\pi }{2}}_{-\frac{\pi }{2}}\cos x\, dx=\left[\sin x\right]^{\frac{\pi }{2}}_{-\frac{\pi }{2}}=2$ (II) (D) $\int\limits^{\frac{\pi }{2}}_{0}\sin^2x\, dx=\int\limits^{\frac{\pi }{2}}_{0}\frac{1-\cos 2x}{2}dx=\frac{\pi}{4}$ (III) |
