If ΔABC is a right angled triangle with ∠ABC = 90°, and AC = 10 cm, BC = 8 cm, then the length of AB is :

12 cm 2 cm 18 cm 6 cm

6 cm

We know that, AC2 = AB2 + BC2 We have, ∠ABC = 90°  AC = 10 cm BC = 8 cm = 102 = (AB)2 + (8)2 = AB2 = 100 – 64 = 36 = AB = 6 cm