What is the least number of square tiles required to pave the floor of a room 30m and 34cm long and 18m and 4cm broad?
Answer & explanation
Correct answer: option 1
30m &34cm = 3034cm
18m &04cm = 1804cm
Now,
HCF of 3034 & 1804= 41 = side of a square tile
No. of tiles (required) = \(\frac{area\;of\;floor}{area\;of\;1\;tile}\)
= \(\frac{3034 × 1804}{41 × 41}\) = 3256