What is the least number of square tiles required to pave the floor of a room 30m and 34cm long and 18m and 4cm broad?

3256 4256 4256 2256

3256

30m &34cm = 3034cm 18m &04cm = 1804cm Now, HCF of 3034 & 1804= 41 = side of a square tile No. of tiles (required) = \(\frac{area\;of\;floor}{area\;of\;1\;tile}\)                                   = \(\frac{3034 × 1804}{41 × 41}\) = 3256