If a person goes from home to his college at a speed of 12 km/h, he reaches 7 minutes early. If he goes at a speed of 8 km/h, he reaches 14 minutes late. What is the distance between his home and his college?

8.4 km

Let distance = X km

Time difference = 14 - (-7) = 21 minutes

According to question ,

\(\frac{X}{8}\) -  \(\frac{X}{12}\)= \(\frac{21}{60}\)

\(\frac{X}{24}\) = \(\frac{21}{60}\)

X = 8.4 km

So , Distance is 8.4 km