In the given figure, a =15 m/s2 represents the total acceleration of a particle moving in the clockwise direction in a circle of radius R = 2.5 m at a given instant of time. The speed of the particle is :
Answer & explanation
Correct answer: option 3
a = 15 m/s2 ; r = 2.5 m
Tangential acceleration : at = g sin 30 = 9.8 x 0.5 = 4.9
Radial acceleration : ar = \(\frac{v^2}{r}\) = \(\frac{v^2}{2.5}\)
a = \(\sqrt{a_t^2 + a_r^2}\)
15 = \(\sqrt{4.9^2 + (\frac{v^2}{2.5})^2}\)
⇒ v = 5.9 m/s