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CUET
General Test
Quantitative Reasoning
Trigonometry
If $sin^2 x - 3cos^2x = 0 $, then the value of x (0 < x < 90°) is :
45°
30°
60°
15°
sin²x - 3 cos²x = 0
sin²x = 3 cos²x
tanx = \(\sqrt {3 }\)
{ we know, tan60º = \(\sqrt {3 }\) }
So, x = 60º