If $sin^2 x - 3cos^2x = 0 $, then the value of x (0 < x < 90°) is :
Answer & explanation
Correct answer: option 3
sin²x - 3 cos²x = 0
sin²x = 3 cos²x
tanx = \(\sqrt {3 }\)
{ we know, tan60º = \(\sqrt {3 }\) }
So, x = 60º
If $sin^2 x - 3cos^2x = 0 $, then the value of x (0 < x < 90°) is :
Correct answer: option 3
sin²x - 3 cos²x = 0
sin²x = 3 cos²x
tanx = \(\sqrt {3 }\)
{ we know, tan60º = \(\sqrt {3 }\) }
So, x = 60º