Practicing Success
A, B and C can individually complete a task in 20 days, 16 days and 30 days, respectively. If A and B started working on the task, and they worked for 4 days and left, then the number of days required by C to finish the remaining task is: |
$16 \frac{1}{2}$ days 13 days 10 days $12 \frac{1}{2}$ days |
$16 \frac{1}{2}$ days |
A = 20 days, B = 16 days, C = 30 days, ⇒ A + B worked for 4 days = (12 + 15) x 4 = 108 units. ..(Efficiency × Days = Total work) ⇒ Remaining work = 240 - 108 = 132 units, ⇒ Time required by C to complete 132 units = \(\frac{132}{8}\) = \( { 16}_{2 }^{ 1} \) days. ..(\(\frac{Work}{Efficiency}\) = Time) |