$7≤3x+\frac{11}{2}≤11$
Answer & explanation
Correct answer: option 4
The correct answer is option (4) : $[1,\frac{11}{3}]$
$7≤3x+\frac{11}{2}≤11$
$14≤3x+11≤22$
$14-11≤3x≤22-11$
$3≤3x≤11$
$1≤x≤\frac{11}{3}$
∴ Solution set is { x : x ∈ R, 1 ≤ x ≤ $\frac{11}{3}$ } i.e $[1,\frac{11}{3}]$