The maximum and minimum amplitudes of a modulated carrier wave are 1000 mV and 200 mV respectively, the modulation index is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{2}{3}$
The modulation index (m) of an AM waves is -
$m=\frac{A_{max}-A_{min}}{A_{max}+A_{min}}$
$=\frac{1000-200}{1000+200}=\frac{2}{3}$