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For a Common-Emitter amplifier, the audio signal voltage across the collector resistance of 2 kΩ is 2 V. Suppose the current amplification factor of the transistor is 100. The base resistance is 1 kΩ. The input signal voltage will be: |
0.02 V 0.04 V 0.03 V 0.01 V |
0.04 V |
$ V_{in} = \frac{V_{out}R_{CE}}{\beta R_{BE}}= 0.04V$ |
