The relative lowering of vapor pressure is equal to the
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → mole fraction of solute
This is directly stated by Raoult's Law for relative lowering of vapor pressure:
$ \frac{P^0-P_{s}}{P^0}=X_{\text{solute}} $
Where:
$ P^0$ = vapor pressure of pure solvent
$ P_{s}$ = vapor pressure of solution
$ X_{\text{solute}}$ = mole fraction of solute