A circular wire of diameter 77 cm is bent in the form of a rectangle whose length is 142% of its breadth. What is the area of the rectangle? (Take $\pi = \frac{22}{7}$)
Answer & explanation
Correct answer: option 3
We know that,
Perimeter of the rectangle = 2(l + b)
Area of Rectangle = length × breadth
We have,
Length = 142% of breadth
142% = \(\frac{71}{50}\)
Diameter of circle = 77 cm
Circumference of circle = 2πr = 77 × \(\frac{22}{7}\) = 242
Length of the rectangle = 71a and breadth = 21a
Perimeter of the rectangle = 242
= 2(71a + 50a) = 242
= 121x = \(\frac{242}{2}\) = 121
= a = 1
Area of rectangle = 71a × 50a = 71 × 1 × 50 × 1 = 3550 cm2