A circular wire of diameter 77 cm is bent in the form of a rectangle whose length is 142% of its breadth. What is the area of the rectangle? (Take $\pi = \frac{22}{7}$)

3550 sq.cm

 We know that,

Perimeter of the rectangle = 2(l + b)

Area of Rectangle = length × breadth

We have,

Length = 142% of breadth

142% = \(\frac{71}{50}\)

Diameter of circle = 77 cm

Circumference of circle = 2πr  = 77 × \(\frac{22}{7}\) = 242

Length of the rectangle = 71a and breadth = 21a

Perimeter of the rectangle = 242

= 2(71a + 50a) = 242

= 121x = \(\frac{242}{2}\) = 121

= a = 1

Area of rectangle = 71a × 50a = 71 × 1 × 50 × 1 = 3550 cm²