If \(\frac{2sinθ - cosθ}{cosθ + 3sinθ}\) = 1 then value of cotθ is?
Answer & explanation
Correct answer: option 1
\(\frac{2sinθ - cosθ}{cosθ + 3sinθ}\) = 1
⇒ \(\frac{sinθ(2-cotθ)}{sinθ (cotθ + 3)}\) = 1
⇒ 2 - cotθ = cotθ + 3
⇒ 2cotθ = -1
⇒ cotθ = -\(\frac{1}{2}\)