If \(\frac{2sinθ - cosθ}{cosθ + 3sinθ}\) = 1 then value of cotθ is?

-\(\frac{1}{2}\) \(\frac{2}{3}\)   \(\frac{1}{2}\) \(\frac{1}{3}\)

-\(\frac{1}{2}\)

\(\frac{2sinθ - cosθ}{cosθ + 3sinθ}\) = 1 ⇒ \(\frac{sinθ(2-cotθ)}{sinθ (cotθ + 3)}\) = 1 ⇒ 2 - cotθ = cotθ + 3 ⇒ 2cotθ = -1 ⇒ cotθ = -\(\frac{1}{2}\)