Arrange $k, \alpha , \beta $ and $\mu $ in descending order :

A. If $y=\frac{1}{x}$ then $\left[\frac{d^2y}{dx^2}\right]_{x=\frac{1}{2}}=k$

A. If $y=\frac{2}{x}$ then $\left[\frac{d^2y}{dx^2}\right]_{x=2}=\alpha $

C. If $y=\frac{1}{x+1}$ then $\left[\frac{d^2y}{dx^2}\right]_{x=1}=\beta $

D. If $y=log_e(x+1)$ then $\left[\frac{d^2y}{dx^2}\right]_{x=1}=\mu $

Choose the correct answer from the option sgiven below :

$k > \alpha > \beta > \mu $