X and Y are 270 km apart. At 9:00 a.m. buses A and B left X and Y for Y and X respectively. If the speeds of A and B are 50 kmph and 40 kmph respectively, find their meeting time.
Answer & explanation
Correct answer: option 2
Speed = \(\frac{ Distance}{ Time}\)
50 + 40 = \(\frac{270}{ Time}\)
Time = \(\frac{270}{ 90}\)
Time = 3 hour
Thus, they will meet after 3 hours i.e. 9:00 am + 3 hours = 12:00 pm