X and Y are 270 km apart. At 9:00 a.m. buses A and B left X and Y for Y and X respectively. If the speeds of A and B are 50 kmph and 40 kmph respectively, find their meeting time.

11.00 a.m 12.00 Noon 1.00 p.m 2.00 p.m

12.00 Noon

Speed = \(\frac{ Distance}{ Time}\) 50 + 40 = \(\frac{270}{ Time}\) Time = \(\frac{270}{ 90}\) Time = 3 hour Thus, they will meet after 3 hours i.e. 9:00 am + 3 hours = 12:00 pm