CUET Preparation Today
In the interval [-5, -3], the function $f(x)=(x+1)(x-3)$ is: |
strictly increasing strictly decreasing neither increasing nor decreasing first increasing then decreasing |
strictly decreasing |
The correct answer is Option (2) → strictly decreasing $f(x)=(x+1)(x-3)$ $f'(x)=x-3+x+1=0⇒x=2$
for $x<2$ f(x) is strictly decreasing hence for $x∈[-5,-3]$ f(x) is strictly decreasing |
