Arrange the following in the increasing order of their solubility in n-octane on the basis of their solute-solvent interaction:
(A) $KCl$
(B) $CH_3OH$
(C) $CH_3CN$
(D) Cyclohexane
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A), (B), (C), (D)
-
n-Octane is non-polar, so it dissolves non-polar substances best (“like dissolves like”).
-
(A) KCl → Ionic → least soluble in non-polar solvent
-
(B) CH₃OH (methanol) → Polar + hydrogen bonding → very low solubility
-
(C) CH₃CN (acetonitrile) → Polar but less hydrogen bonding → slightly better than methanol
-
(D) Cyclohexane → Non-polar → most soluble
The increasing order of solubility in n-octane is:
(A) KCl < (B) CH₃OH < (C) CH₃CN < (D) Cyclohexane