The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146 x 10^-3 S cm^-1?

0.219 cm^-1

Conductivity = Conductance x Cell constant

Κ = G x σ 

Κ = \(\frac{1}{R}\) x σ 

0.146 x 10^-3 = \(\frac{1}{1500}\) x σ

σ = 0.146 x 10^-3 x 1500 = 0.219 cm^-1