The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146 x 10-3 S cm-1?
Answer & explanation
Correct answer: option 1
Conductivity = Conductance x Cell constant
Κ = G x σ
Κ = \(\frac{1}{R}\) x σ
0.146 x 10-3 = \(\frac{1}{1500}\) x σ
σ = 0.146 x 10-3 x 1500 = 0.219 cm-1