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Instantaneous displacement current of 1.0 A in the space between the parallel plate of 1 μF capacitor can be established by changing potential difference of |
10−6Vs−1 106Vs−1 1 Vs−1 0.1 Vs−1 |
106Vs−1 |
$\frac{Q}{t}=\frac{CV}{t} or i_d = C(\frac{V}{t})$ $\Rightarrow \frac{V}{t}=\frac{i_d}{C}=\frac{1.0}{10^{-6}}Vs^{-1} = 10^6 Vs^{-1}$ |
