If X : Y = 7 : 3 then the value of \(\frac{X^2+Y^2}{X^2-Y^2}\)

\(\frac{28}{19}\) \(\frac{28}{23}\) \(\frac{29}{20}\) \(\frac{29}{21}\)

\(\frac{29}{20}\)

X : Y = 7 : 3 Put X = 7 and Y = 3 \(\frac{X^2+Y^2}{X^2-Y^2}\) = \(\frac{7^2+ 3^2}{7^2- 3^2}\) = \(\frac{49 + 9}{49 - 9}\) = \(\frac{58}{40}\) = \(\frac{29}{20}\)