If X : Y = 7 : 3 then the value of \(\frac{X^2+Y^2}{X^2-Y^2}\)
Answer & explanation
Correct answer: option 3
X : Y = 7 : 3
Put X = 7 and Y = 3
\(\frac{X^2+Y^2}{X^2-Y^2}\) = \(\frac{7^2+ 3^2}{7^2- 3^2}\) = \(\frac{49 + 9}{49 - 9}\) = \(\frac{58}{40}\) = \(\frac{29}{20}\)