Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

The shortest distance between the lines \(\vec{r}=\left(\hat{i}+2\hat{j}+\hat{k}\right)+\lambda \left(\hat{i}-\hat{j}-\hat{k}\right)\) and \(\vec{r}=\left(2\hat{i}-\hat{j}-\hat{k}\right)+\lambda \left(2\hat{i}+\hat{j}+2\hat{k}\right)\) is 

Options:

\(3\sqrt{2}\)

\(\frac{3\sqrt{2}}{2}\)

\(\frac{3}{2}\)

\(3\)

Correct Answer:

\(\frac{3\sqrt{2}}{2}\)

Explanation:

Recall the formula for shortest distance