Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

A capacitor is a system of two conductors separated by an insulating medium. Capacitance of this systems is determined purely geometrically, by the shapes, size and relative position of the conductors. The medium between the two conductor can be air or a dielectric. The way the dielectric is inserted accordingly by capacitance changes. Electric energy is stored in the capacitors. The capacitor can be connected in series or in parallel in an electric circuit.

An electrical technician required a capacitance of 2 μF. in a circuit across a potential difference of 1 kV. A large no of 1 μF capacitors are available to him each of which can withstand a potential difference of not more than 300 V. The minimum number of capacitor required for the arrangement will be.

Options:

18

24

32

36

Correct Answer:

32

Explanation:

The correct answer is Option (3) → 32

Here Cnet = 2 μF

Applied voltage = 1000 V

The circuit can be arranged as

Voltage on each capacitor = 250 V

And, capacitance of each branch = $\frac{1}{4} \mu F$

∴  $C_{\text {net }}=\left(\frac{1}{4}\right) 8=2 \mu F$

So, total 8 rows are required

Thus minimum 32 capacitors are required for this setup