In the reaction, \((CH_3)_3C-O-CH_3 + HI \longrightarrow \text{ Products}\)

\(CH_3OH\) and \((CH_3)_3CI\) are the products and not \(CH_3I\) and \((CH_3)_3C-OH\). It is because

(A) in step 2 of the reaction the departure of leaving group \((HO-CH_3)\) creates less stable carbocation

(B) in step 2 of the reaction the departure of leaving group \((HO-CH_3)\) creates more stable carbocation

(C) the reaction follows \(S_N1\) mechanism

(D) the reaction follows \(S_N2\) mechanism 

Choose the correct answers from the options given below:

1. B and D only

2. B and C only

3. A and D only

4. A and C only

B and C only

The correct answer is option 2. B and C only.

Let us look at the reaction:

Now, let us look at the mechanism of the reaction: