In the reaction, \((CH_3)_3C-O-CH_3 + HI \longrightarrow \text{ Products}\)
\(CH_3OH\) and \((CH_3)_3CI\) are the products and not \(CH_3I\) and \((CH_3)_3C-OH\). It is because
(A) in step 2 of the reaction the departure of leaving group \((HO-CH_3)\) creates less stable carbocation
(B) in step 2 of the reaction the departure of leaving group \((HO-CH_3)\) creates more stable carbocation
(C) the reaction follows \(S_N1\) mechanism
(D) the reaction follows \(S_N2\) mechanism
Choose the correct answers from the options given below:
1. B and D only
2. B and C only
3. A and D only
4. A and C only
Answer & explanation
Correct answer: option 2
The correct answer is option 2. B and C only.
Let us look at the reaction:
Now, let us look at the mechanism of the reaction:
