Probability distribution of random variable X is
| X | -2 | -1 | 0 | 1 | 2 |
| P(X) | 2/11 | 1/11 | 4/11 | 3/11 | 1/11 |
Then the value of E(X) is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 0
The expected value is \(E(X) = \sum x\,P(x)\):
\( \displaystyle E(X) = (-2)\cdot\frac{2}{11} + (-1)\cdot\frac{1}{11} + 0\cdot\frac{4}{11} + 1\cdot\frac{3}{11} + 2\cdot\frac{1}{11} \)
\( \displaystyle E(X) = \frac{-4 - 1 + 0 + 3 + 2}{11} = \frac{0}{11} = 0 \)