Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If x + y + z = 11 , xy + yz + zx = -6 , and x3 + y3 + z3 = 1604, then the value of xyz is :

Options:

25

4

1

5

Correct Answer:

25

Explanation:

We know that =

= x³ + y³ + z³ - 3xyz = (x + y + z){(x + y + z)2 - 3(xy + yz + zx)}

= 1604 - 3xyz = 11{121 - 3(- 6)}

= 1604 - 1529 = 3xyz

= xyz = \(\frac{75}{3}\)

= xyz = 25