
Answer & explanation
Correct answer: option 4
$ B = \mu_0 nI $
$ I = \frac{B}{\mu_0 n} = \frac{ 20\times 10^{-3}}{4\pi \times 10^{-7} \times 2000} = 8 A$

Correct answer: option 4
$ B = \mu_0 nI $
$ I = \frac{B}{\mu_0 n} = \frac{ 20\times 10^{-3}}{4\pi \times 10^{-7} \times 2000} = 8 A$