If $x-\frac{1}{x}=13,$ then the value of $x^2 +\frac{1}{x^2}$ is :

171 169 167 165

171

If $x-\frac{1}{x}=13,$ then the value of $x^2 +\frac{1}{x^2}$ is : If $K-\frac{1}{K}=n$ then, $K^2+\frac{1}{K^2}$ = n2 + 2 $x^2 +\frac{1}{x^2}$ = 132 + 2 = 171