The two parallel sides of a trapezium are 27 cm and 13 cm respectively. If the height of the trapezium is 8 cm, then what is its area in m2?
Answer & explanation
Correct answer: option 3
We know that,
Area of trapezium = \(\frac{1}{2}\)× (sum of parallel sides) × (distance between parallel sides)
We have,
Length of parallel sides = 27 cm and 13 cm
Height = 8 cm
Now,
27 cm = 0.27 m
13 cm = 0.13 m
8 cm = 0.08 m
Area of trapezium = \(\frac{1}{2}\) × (0.27 + 0.13) × (0.08 )
= \(\frac{0.4}{2}\) × 0.08 = 0.20 × 0.08
= 0.016 m2