Practicing Success
CUET Preparation Today
CUET
Physics
Semiconductors and Electronic Devices
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$\text{Voltage Gain}A_v = \beta \frac{R_o}{R_i} = 60\times \frac{5}{2} = 150$
$\text{Output Voltage} V_o = V_i \times 150 = 1.8V$
$\text{Power Gain} A_p = A_v \times \beta = 150\times 60 = 9000$