Practicing Success
If x + \(\frac{1}{y}\) = 1, y + \(\frac{1}{z}\) = 1, find the value of (z + \(\frac{1}{x}\)). |
1 -1 0 \(\frac{-1}{2}\) |
1 |
Let x = \(\frac{1}{2}\), y = 2 and z = -1 \(\frac{1}{2}\) + \(\frac{1}{2}\) = 1 2 - 1 = 1 (satisfied) so, z + \(\frac{1}{x}\) = - 1 + 2 = 1 |