If x + \(\frac{1}{y}\) = 1, y + \(\frac{1}{z}\) = 1, find the value of (z + \(\frac{1}{x}\)).
Answer & explanation
Correct answer: option 1
Let x = \(\frac{1}{2}\), y = 2 and z = -1
\(\frac{1}{2}\) + \(\frac{1}{2}\) = 1
2 - 1 = 1 (satisfied)
so, z + \(\frac{1}{x}\) = - 1 + 2 = 1