Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

Dimensions of Capacitance in a circuit, in terms of dimension of mass M, length L, time T and current I, would be

Options:

$[ML^2T^{-3}I^{-1}]$

$[ML^2T^{-2}]$

$ [M^{-1}L^{-2}T^4 I^2]$

$[ML^2T^{-1}I^{-1}]$

Correct Answer:

$ [M^{-1}L^{-2}T^4 I^2]$

Explanation:

Energy is given as $ U = \frac{q^2}{2C} $

$\Rightarrow \text{Dimension of Capacitance is } [C] = \frac{[q^2]}{[U]} = \frac{[I^2T^2]}{[ML^2T^{-2}]} = [M^{-1}L^{-2}T^4 I^2]$