Dimensions of Capacitance in a circuit, in terms of dimension of mass M, length L, time T and current I, would be
Answer & explanation
Correct answer: option 3
Energy is given as $ U = \frac{q^2}{2C} $
$\Rightarrow \text{Dimension of Capacitance is } [C] = \frac{[q^2]}{[U]} = \frac{[I^2T^2]}{[ML^2T^{-2}]} = [M^{-1}L^{-2}T^4 I^2]$