A 10 pF capacitor is connected to a 24 V battery. The electrostatic energy stored in the capacitor is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( 2.88 \times 10^{-9}\,\mathrm{J} \)
The energy stored in a capacitor charged to potential difference \( V \) is \( U = \frac{1}{2}CV^{2} \).
\( C = 10\,\mathrm{pF} = 10\times10^{-12}\,\mathrm{F} = 10^{-11}\,\mathrm{F} \)
\( V = 24\,\mathrm{V} \)
\( \displaystyle U = \frac{1}{2} \times 10^{-11} \times (24)^{2} = \frac{1}{2} \times 10^{-11} \times 576 = 2.88\times10^{-9}\,\mathrm{J} \)
Note: NTA picked this question from an NCERT (2026-27) exercise and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
