In right angled triangle ABC; \(\angle\)

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

In right angled triangle ABC; \(\angle\)A = 90°; AB : BC = 1 : 2; then value of sin A + cos B is?

Options:

\(\frac{3}{2}\)

\(\frac{1}{2}\)

\(\frac{2 + \sqrt { 3}}{2}\)

Correct Answer:

\(\frac{3}{2}\)

Explanation:

⇒ sin A = sin 90° = 1, and

⇒ cos B = \(\frac{AB}{BC}\) = \(\frac{1}{2}\)

and

∴ sin A + cos B = 1 + \(\frac{1}{2}\) = \(\frac{3}{2}\)