Practicing Success
The average weight of 10 boys is increased by 3 kg if one of them weighing 40 kg is replaced by a new boy. The weight of the new boy is: |
45 kg 70 kg 80 kg 40 kg |
70 kg |
Average of 10 boys = $\frac{Sum\; of\; weight}{10}$ Let the weight of 9 of them be $x$, The 10th boy, who weighs 40 kg is replaced by a new boy. Original weight average was $\frac{x+40}{10}$ This, increases by 3 when new boy(of weight say, $y$) is added, ⇒ $\frac{x+y}{10}$ = $\frac{x+40}{10}$ + 3 ⇒ ($x + y$) = ($x + 40$) + 3 x 10 ⇒ $y$ = 70 Thus, the weight of the new boy was 70 kg. |