The length of a rope, by which a calf is tied, is decreased from 9 m to 5 m. Find the decrease in the area that can be grazed by the calf. [Use π = $\frac{22}{7}$]

176 m²

The length of a rope, by which a calf is tied, is decreased from 9 m to 5 m

The length of a rope, by which a calf is tied, is decreased from 9 m to 5 m. Find the decrease in the area that can be grazed by the calf.

We know that,

Area of the circle = π r² 

= Old Area = π (9)²  = 81π 

= New Area = π (5)² = 25π 

So,  change in Area

= 81π - 25π 

= 56π = (56 × \(\frac{22}{7}\)) = 176 m²