A alone can do a job in 30 days while B alone can do it in 45 days. A starts the job and after 5 days B joins him. After few more days, C joins them and they together finish the job. If C has done 16\(\frac{2}{3}\)% of the job, then in how many days was the job done?
Answer & explanation
Correct answer: option 2
⇒ C does 16\(\frac{2}{3}\)% = \(\frac{1}{6}\) of the work i.e 15
Then, A + B do 75 units of work
⇒ A alone does the work in 1st 5 days = 3 x 5 = 15
Remaining work (done by A and B together) = 75 - 15 = 60
⇒ A + B does the remaining work in = \(\frac{60}{5}\) = 12 days
So,
The work completed in = 5 + 12 = 17 days