Practicing Success
A force \(\vec{F} = \alpha\hat{i} + 3\hat{j} + 6\hat{k}\) is acting at a point \(\vec{r} = 2\hat{i} - 6\hat{j} - 12\hat{k}\). The value of \(\alpha\) for which angular momentum about origin is conserved is : |
1 - 1 2 zero |
- 1 |
Conservation of Angular Momentum ⇒ \(\tau = 0 \) \(\vec{r} × \vec{F} = 0\) ⇒ \(\frac{F_x}{x} = \frac{F_y}{y} = \frac{F_z}{z} \) \(\frac{\alpha}{2} = \frac{3}{-6} = \frac{6}{-12} \) ⇒ \(\alpha = -1 \) |