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Practicing Success
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For what value of x will |adj A| =-12 if A = \(\begin{bmatrix}x^2 & x\\7 & 1 \end{bmatrix}\)? |
x=3 or x=4 x=-3 or x=-4 x=3 or x=-4 x=-3 or x=4 |
x=3 or x=4 |
|adj A| = \( { |A| }^{ n-1 } \) -12 = \( { |A| }^{ 2-1 } \) -12 = |A| -12 = \( { x }^{ 2 } -7x\) 0 = \( { x }^{ 2 } -7x\)+12 0 = (x-3)(x-4) x= 3 or x=4 |
