Find the general solution to the following differential equation :
\(\frac{dy}{dx}\) = -4xy2 , y(0) = 1
Answer & explanation
Correct answer: option 4
dy = -4xy2 . dx and then integrate to get :
$y = \frac{1}{2x^2} + C $
Find the general solution to the following differential equation :
\(\frac{dy}{dx}\) = -4xy2 , y(0) = 1
Correct answer: option 4
dy = -4xy2 . dx and then integrate to get :
$y = \frac{1}{2x^2} + C $